OFFSET
1,1
LINKS
Andrew Howroyd, Table of n, a(n) for n = 1..100
FORMULA
a(2n+1) = A106367(2n+1)/2 for n > 0, a(2n) = (A106367(2n) + 5*4^n/2)/2. - Andrew Howroyd, Mar 12 2017
EXAMPLE
All solutions for n=3:
..1....1....1....2....3....2....1....2....1....1
..2....2....3....3....4....4....4....3....3....2
..4....3....4....4....5....5....5....5....5....5
MATHEMATICA
T[n_, k_] := If[n == 1, k, (DivisorSum[n, EulerPhi[n/#]*(k - 1)^# &]/n + If[OddQ[n], 1 - k, k*(k - 1)^(n/2)/2])/2]; a[n_] = T[n, 5]; Array[a, 26] (* Jean-François Alcover, Nov 01 2017, after Andrew Howroyd *)
CROSSREFS
KEYWORD
nonn
AUTHOR
R. H. Hardin, Feb 27 2012
EXTENSIONS
a(21)-a(26) from Andrew Howroyd, Mar 12 2017
STATUS
approved