OFFSET
2,1
COMMENTS
s = {2,3,5,7,11}; R = circumradius (A200257).
K = sum((s(n)/4)(4*R^2-s(n)^2)^(1/2), n=1..5) = 41.9529923613808924252...
This is maximal area of pentagon with sides 2, 3, 5, 7, 11.
MATHEMATICA
digits = 86; r = x /. FindRoot[ Sum[ ArcSin[ Prime[n]/2/x], {n, 5}] == Pi, {x, 5}, WorkingPrecision -> digits+10] // Re; Sum[p/4*(4*r^2 - p^2)^(1/2), {p, Prime /@ Range[5]}] // RealDigits[#, 10, digits]& // First (* Jean-François Alcover, Feb 15 2013, after Zak Seidov *)
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
Zak Seidov, Nov 18 2011
STATUS
approved