A198463 Consider triples a<=b<c where (a^2+b^2-c^2)/(c-a-b) =3, ordered by a and then b; sequence gives b values.

3, 7, 12, 18, 6, 11, 25, 15, 33, 42, 10, 15, 52, 30, 63, 36, 75, 14, 19, 27, 88, 102, 75, 117, 18, 23, 42, 65, 133, 150, 30, 39, 168, 22, 27, 60, 92, 187, 102, 207, 42, 54, 228, 22, 26, 31, 81, 250, 51, 135, 273, 147, 297, 30, 35, 105, 322, 45, 66, 84, 348

Offset

1,1

Comments

The definition can be generalized to define Pythagorean k-triples a<=b<c where (a^2+b^2-c^2)/(c-a-b)=k, or where for some integer k, a(a+k) + b(b+k) = c(c+k).

If a, b and c form a Pythagorean k-triple, then na, nb and nc form a Pythagorean nk-triple.

A triangle is defined to be a Pythagorean k-triangle if its sides form a Pythagorean k-triple.

If a, b and c are the sides of a Pythagorean k-triangle ABC with a<=b<c, then cos(C) = -k/(a+b+c+k) which proves that such triangles must be obtuse when k>0 and acute when k<0. When k=0, the triangles are Pythagorean, as in the Beiler reference and Ron Knott’s link. For all k, the area of a Pythagorean k-triangle ABC with a<=b<c equals sqrt((2ab)^2-(k(a+b-c))^2))/4.

References

A. H. Beiler, Recreations in the Theory of Numbers, Dover, New York, 1964, pp. 104-134.

Links

Table of n, a(n) for n=1..61.

Ron Knott, Pythagorean Triples and Online Calculators

Example

2*5 + 3*6 = 4*7
3*6 + 7*10 = 8*11
4*7 +12*15 = 13*16
5*8 + 18*21 = 19*22
6*9 = 6*9 = 9*12
6*9 = 11*14 = 13*16

Prog

(True BASIC)
input k
for a = (abs(k)-k+4)/2 to  40
for b = a to (a^2+abs(k)*a+2)/2
  let t = a*(a+k)+b*(b+k)
   let c =int((-k+ (k^2+4*t)^.5)/2)
    if c*(c+k)=t then print a; b; c,
next b
print
next a
end

Crossrefs

Cf. A103606, A198454-A198469.

Sequence in context: A298022 A227133 A170883 * A140778 A095115 A310249

Adjacent sequences: A198460 A198461 A198462 * A198464 A198465 A198466

Keyword

nonn

Author

Charlie Marion, Nov 26 2011

Status

approved