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A197917 Suppose n has prime factorization n=p1^a1*p2^a2*...*pk^ak and that D(n) is A006218, then n has all D(ai) even. 0

%I #14 Jan 15 2022 22:29:59

%S 1,16,32,64,81,128,243,256,625,729,1296,2187,2401,2592,3125,3888,5184,

%T 6561,7776,10000,10368,11664,14641,15552,15625,16807,20000,20736,

%U 23328,28561,31104,34992,38416,40000,46656,50000,50625,62208,65536,69984,76832,78125

%N Suppose n has prime factorization n=p1^a1*p2^a2*...*pk^ak and that D(n) is A006218, then n has all D(ai) even.

%C Equivalently, for all exponents e in the factorization of n, floor(sqrt(e)) is even. [_Charles R Greathouse IV_, Oct 20 2011]

%H StackExchange, <a href="http://math.stackexchange.com/questions/73354/two-dirichlets-series-related-to-the-divisor-summatory-function-and-to-the-riem">Question 73354</a>

%o (PARI) is(n)=my(f=factor(n)[,2]);for(i=1,#f,if(sqrtint(f[i])%2,return(0)));1 \\ _Charles R Greathouse IV_, Oct 20 2011

%Y Cf. A006218.

%K nonn

%O 1,2

%A _A. Neves_, Oct 19 2011

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Last modified April 25 23:59 EDT 2024. Contains 371989 sequences. (Running on oeis4.)