

A191390


Triangle read by rows: T(n,k) is the number of dispersed Dyck paths of length n with k horizontal segments.


1



1, 0, 1, 1, 1, 0, 3, 2, 3, 1, 0, 8, 2, 5, 8, 7, 0, 22, 12, 1, 14, 22, 31, 3, 0, 64, 50, 12, 42, 64, 117, 28, 1, 0, 196, 184, 78, 4, 132, 196, 416, 162, 18, 0, 625, 648, 390, 52, 1, 429, 625, 1452, 762, 159, 5, 0, 2055, 2256, 1707, 392, 25, 1430, 2055, 5062, 3225, 1012, 85, 1, 0, 6917, 7868, 6954, 2280, 285, 6
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OFFSET

0,7


COMMENTS

A dispersed Dyck paths of length n is a Motzkin paths of length n with no (1,0)steps at positive heights. A horizontal segment is a maximal sequence of consecutive (1,0)steps.
Row n has 1 + ceiling(n/3) entries.
Sum of entries in row n is binomial(n, floor(n/2)) = A001405(n).
T(2n,0) = A000108(n) (the Catalan numbers); T(2n+1,0) = 0.
T(2n1,1) = T(2n,1) = A014138(n) (partial sums of Catalan numbers).


LINKS



FORMULA

G.f.: G(t,z) = (2*(1z+t*z))/(1zt*z+(1z+t*z)*sqrt(14*z^2)).


EXAMPLE

T(5,2)=2 because we have (HH)UD(H) and (H)UD(HH), where U=(1,1), D=(1,1), H=(1,0) (the horizontal segments are shown between parentheses).
Triangle starts:
1;
0, 1;
1, 1;
0, 3;
2, 3, 1;
0, 8, 2;
5, 8, 7;
0, 22, 12, 1;


MAPLE

G := (2*(1z+t*z))/(1zt*z+(1z+t*z)*sqrt(14*z^2)): Gser := simplify(series(G, z = 0, 20)): for n from 0 to 17 do P[n] := sort(coeff(Gser, z, n)) end do: for n from 0 to 17 do seq(coeff(P[n], t, k), k = 0 .. ceil((1/3)*n)) end do; # yields sequence in triangular form


CROSSREFS



KEYWORD

nonn,tabf


AUTHOR



STATUS

approved



