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Positions of 1 in A190201; complement of A190202.
3

%I #8 Dec 28 2017 03:38:06

%S 2,3,4,6,8,11,12,15,20,21,22,24,25,28,29,31,33,37,38,40,41,42,44,46,

%T 49,50,53,55,58,59,62,63,66,67,69,71,72,75,76,78,80,82,84,87,88,91,93,

%U 96,97,100,101,104,105,107,109,110,113,114,116,118,122,125,126,127,129,131,134,135,138,142,143,144,145,147,148,151,152,154

%N Positions of 1 in A190201; complement of A190202.

%H G. C. Greubel, <a href="/A190203/b190203.txt">Table of n, a(n) for n = 1..5550</a>

%t u = 5^(1/2); v = 1/u;

%t f[n_] := Floor[n*u + n*v] - Floor[n*u] - Floor[n*v]

%t t = Table[f[n], {n, 1, 120}] (*A190201*)

%t Flatten[Position[t, 0]] (*A190202*)

%t Flatten[Position[t, 1]] (*A190203*)

%Y Cf. A190201, A190202.

%K nonn

%O 1,1

%A _Clark Kimberling_, May 05 2011