%I #15 Nov 18 2013 11:03:54
%S 0,1,2,3,0,1,2,3,0,1,2,3,0,1,2,3,0,0,1,2,3,0,1,2,3,0,1,2,3,0,1,2,3,0,
%T 1,1,2,3,0,1,2,3,0,1,2,3,0,1,2,3,0,1,2,2,3,0,1,2,3,0,1,2,3,0,1,2,3,0,
%U 1,2,3,3,0,1,2,3,0,1,2,3,0,1,2,3,0,1,2,3,0,0,1,2,3,0,1,2,3,0,1,2,3,0,1,2,3,0,1,1,2,3,0,1,2,3,0,1,2,3,0,1,2,3,0,1,2,2,3,0,1,2,3,0
%N [4rn]-4[rn], where r=sqrt(5) and [ ]=floor.
%C Suppose, in general, that a(n)=[(bn+c)r]-b[nr]-[cr]. If r>0 and b and c are integers satisfying b>=2 and 0<=c<=b-1, then 0<=a(n)<=b. The positions of 0 in the sequence a are of interest, as are the position sequences for 1,2,...,b. These b+1 (or b) position sequences comprise a partition of the positive integers.
%H Ivan Panchenko, <a href="/A189480/b189480.txt">Table of n, a(n) for n = 1..1000</a>
%t r=Sqrt[5];
%t f[n_]:=Floor[4 n*r]-4*Floor[n*r];
%t t=Table[f[n],{n,1,320}] (*A189480*)
%t Flatten[Position[t,0]] (*A190813*)
%t Flatten[Position[t,1]] (*A190883*)
%t Flatten[Position[t,2]] (*A190884*)
%t Flatten[Position[t,3]] (*A190885*)
%Y Cf. A190813, A190883, A190884, A190885.
%K nonn
%O 1,3
%A _Clark Kimberling_, Apr 23 2011