A189203 Zero-one sequence based on the sequence n(n+1)(2n+1)/6: a(A000330(k))=a(k); a(v(k))=1-a(k), where v=complement(A000330) and a(1)=0.

0, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 1, 0, 0, 0, 1, 1, 1, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1

Offset

1

Links

Table of n, a(n) for n=1..135.

Mathematica

u[n_] := n(n+1)/(2n+1)/6; (*A000330*)
a[1] = 0; a[2]=1; h = 128;
c = (u[#1] &) /@ Range[2h];
d = (Complement[Range[Max[#1]], #1] &)[c];
Table[a[d[[n]]] = 1 - a[n], {n, 1, h - 1}]; (*A189203*)
Table[a[c[[n]]] = a[n], {n, 1, h}]   (*A189203*)
Flatten[Position[%, 0]]  (*A189204*)
Flatten[Position[%%, 1]] (*A189205*)

Crossrefs

Cf. A188967, A189204, A189205.

Sequence in context: A189014 A189017 A189132 * A296028 A165263 A108737

Adjacent sequences: A189200 A189201 A189202 * A189204 A189205 A189206

Keyword

nonn

Author

Clark Kimberling, Apr 18 2011

Status

approved