|
%I #11 Dec 14 2017 19:58:06
%S 2,5,10,13,18,23,26,31,34,39,44,47,52,57,60,65,68,73,78,81,86,89,94,
%T 99,102,107,112,115,120,123,128,133,136,141,146,149,154,157,162,167,
%U 170,175,178,183,188,191,196,201,204,209,212,217,222,225,230,233,238,243,246,251,256,259,264,267,272,277,280
%N Positions of 0 in A188433; complement of A188435.
%C See A188433.
%C Is a(n) = A101868(n-1) for n>1? - R. J. Mathar, Apr 01 2011
%C Yes: this follows from A188433(n) = 1 - A188009(n), for n > 2, using [-x] = -[x] - 1 for non-integer x. This implies the above, A188434(n) = A101868(n+1) = A101866(1,n+1), and also A188435(n) = A188010(n+1), for all n > 1. - _M. F. Hasler_, Dec 14 2017
%t Flatten[Position[A188433, 0]] (* moved here from A188433 by _M. F. Hasler_, Dec 14 2017 *)
%Y Cf. A188433, A188294.
%K nonn
%O 1,1
%A _Clark Kimberling_, Mar 31 2011
|
