|
|
A184714
|
|
Number of words of numbers x(1), ..., x(n), in 0..3 such that Sum_{i=1..n} i*x(i)^3 = 27*n.
|
|
1
|
|
|
1, 1, 2, 2, 7, 19, 39, 120, 411, 1310, 3862, 11059, 31849, 89615, 247305, 674579, 1812940, 4806211, 12576930, 32509641, 83052304, 209808493, 524424707, 1297623584, 3179903180, 7721053410, 18582920108, 44349211490, 104989527861, 246624184465, 575024282279
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,3
|
|
COMMENTS
|
Coefficient of x^(27*n) in Product_{i=1..n} (1 + x^i + x^(8*i) + x^(27*i)). - Robert Israel, Jul 03 2018
|
|
LINKS
|
|
|
EXAMPLE
|
All solutions for n=5:
0 0 3 2 1 1 2
0 3 0 2 1 2 1
0 3 0 1 2 3 3
0 0 3 3 3 2 1
3 0 0 0 0 1 2
|
|
MAPLE
|
F:= proc(n, s) option remember; if n = 1 or s < 0 then 0 else add(procname(n-1, s-n*j^3), j=0..3) fi end proc:
F(1, 0):= 1: F(1, 1):= 1: F(1, 8):= 1: F(1, 27):= 1:
|
|
MATHEMATICA
|
F[n_, s_] := F[n, s] = If[n == 1 || s < 0, 0, Sum[F[n-1, s-n*j^3], {j, 0, 3}]]; F[1, 0] = 1; F[1, 1] = 1; F[1, 8] = 1; F[1, 27] = 1;
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|