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Is it possible to convert the vector to matrix .unknown number of columns and the number of row is known. Where is the row filled with zeros? Or with holes?

A=[1 2 3 4 5 6 7 8 9]

number of row=3

A=[1 2 3 4

5 6 7 8

9 0 0 0]

Matt J
on 31 Jul 2021

The task is ambiguous without additional specifications on how the number of columns is to be chosen. For example, with the input,

A=[1 2 3 4 5 6 7 8 9 10 11 12 13 14 15];

nrows=3;

there are at least three possible 3-row arrangements that would be valid:

B=[1 2 3 4 5

6 7 8 9 10

11 12 13 14 15]

B=[1 2 3 4 5 6

7 8 9 10 11 12

13 14 15 0 0 0]

B=[1 2 3 4 5 6 7

8 9 10 11 12 13 14

15 0 0 0 0 0 0]

dpb
on 29 Jul 2021

A=1:9;

nRow-3;

>> A=reshape(A,3,[])

A =

1 4 7

2 5 8

3 6 9

>>

The posted in the Q? text above forced four columns, not three (3) rows...

That, of course, is also doable with a little more effort...

A=1:9;

nCol=4;

nZ=ceil(numel(A)/4);

>> reshape([A zeros(1,nCol*nZ-numel(A))],nCol,[]).'

ans =

1 2 3 4

5 6 7 8

9 0 0 0

>>

Image Analyst
on 31 Jul 2021

Matt J
on 29 Jul 2021

No, the solution is ill-defined. Another result with the same number of rows is:

A=[1 2 3

4 5 6

7 8 9]

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