OFFSET
1,1
LINKS
Paolo Xausa, Table of n, a(n) for n = 1..1000
Christian Krause, Proof of formula, Jun 19 2026
Index entries for linear recurrences with constant coefficients, signature (11,-36,36).
FORMULA
a(n) = 4*(2^n-1)*3^(n+1)+4*2^n = 12*6^n-12*3^n+4*2^n. - Zhuorui He, Jun 13 2026
From Stefano Spezia, Jun 21 2026: (Start)
G.f.: 4*x*(11 - 36*x + 36*x^2)/((1 - 2*x)*(1 - 3*x)*(1 - 6*x)).
E.g.f.: 4*(3*exp(6*x) - 3*exp(3*x) + exp(2*x) - 1). (End)
EXAMPLE
Some solutions for 3 X 3:
..1..1..0....0..2..0....2..2..2....3..1..0....1..1..1....2..0..2....1..3..1
..1..3..2....1..3..1....1..1..1....0..2..3....2..2..2....3..1..3....0..2..0
..1..1..0....2..0..2....3..1..3....3..1..0....2..0..2....0..2..0....1..3..1
MATHEMATICA
A183633[n_] := 12*6^n - 12*3^n + 4*2^n;
Array[A183633, 25] (* Paolo Xausa, Jun 22 2026 *)
CROSSREFS
KEYWORD
nonn,easy,changed
AUTHOR
R. H. Hardin, Jan 06 2011
EXTENSIONS
a(9)-a(10) from Zhuorui He, Jun 13 2026
a(11)-a(22) from Christian Krause, Jun 19 2026
STATUS
approved
