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A182835 n+floor(sqrt(2n+3)), complement of A179207. 1

%I #6 Mar 30 2012 18:57:12

%S 3,4,6,7,8,9,11,12,13,14,16,17,18,19,20,21,23,24,25,26,27,28,30,31,32,

%T 33,34,35,36,37,39,40,41,42,43,44,45,46,48,49,50,51,52,53,54,55,56,57,

%U 59,60,61,62,63,64,65,66,67,68,70,71,72,73,74,75,76,77,78,79,80,81,83,84,85,86,87,88,89,90,91,92

%N n+floor(sqrt(2n+3)), complement of A179207.

%F a(n)=n+floor(sqrt(2n+3)).

%t a=2; b=3; Table[n+Floor[(a*n+b)^(1/2)],{n,80}]

%Y Cf. A179207.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, Jan 07 2011

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