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A182358 Numbers n for which the number of divisors of n is congruent to 2 mod 4. 1
2, 3, 5, 7, 11, 12, 13, 17, 18, 19, 20, 23, 28, 29, 31, 32, 37, 41, 43, 44, 45, 47, 48, 50, 52, 53, 59, 61, 63, 67, 68, 71, 73, 75, 76, 79, 80, 83, 89, 92, 97, 98, 99, 101, 103, 107, 109, 112, 113, 116, 117, 124, 127, 131, 137, 139, 147, 148, 149, 151, 153 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

The product of any 2 terms a(i)*a(j) is not a member of the sequence.

tau(n) is congruent to 2 modulo 4 iff only one prime in the prime factorization of n has exponent of the form 4*m + 1, and no prime in the prime factorization of n has exponent of the form 4*k + 3.

LINKS

Charles R Greathouse IV, Table of n, a(n) for n = 1..10000

FORMULA

Terms are of the form p * m^2 * n^4 for any prime p, m coprime to p, and n. - Charles R Greathouse IV, Apr 26 2012

EXAMPLE

The divisors of 12 are: 1, 2, 3, 4, 6, 12 [6 divisors]. 6 is congruent to 2 modulo 4. Thus 12 is a member of this sequence.

PROG

(PARI) {plnt=1 ;  for(k=1, 10^7,

if(numdiv(k) % 4 == 2, print1(k, ", "); plnt++ ; if(100 <  plnt, break() )))}

(PARI) is(n)=my(p=core(n)); isprime(p)&&valuation(n, p)%4==1 \\ Charles R Greathouse IV, Apr 26 2012

(PARI) list(lim)=my(v=List(), t); forprime(p=2, lim, for(m=1, sqrtint(lim\p), if(m%p==0, next); t=p*m^2; for(n=1, sqrtint(sqrtint(lim\t)), listput(v, t*n^4)))); vecsort(Vec(v), , 8) \\ Charles R Greathouse IV, Apr 26 2012

CROSSREFS

This is an extension of A000040 (the prime numbers, which each have 2 divisors).  The definition of this sequence uses A000005 (the number of divisors of n).

Sequence in context: A073085 A316793 A119251 * A212166 A293511 A324515

Adjacent sequences:  A182355 A182356 A182357 * A182359 A182360 A182361

KEYWORD

nonn,easy

AUTHOR

Douglas Latimer, Apr 26 2012

STATUS

approved

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Last modified April 19 20:04 EDT 2019. Contains 322291 sequences. (Running on oeis4.)