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A182049
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Numbers m such that m! is not pandigital in decimal representation.
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3
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0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 24, 25, 26, 28, 29, 30, 32, 38, 41
(list;
graph;
refs;
listen;
history;
text;
internal format)
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OFFSET
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1,3
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COMMENTS
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Conjecture: sequence is finite and a(32) = 41 is the last term.
a(33) > 100000 if it exists. - Chai Wah Wu, Jan 27 2019
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LINKS
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EXAMPLE
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20! = 2432902008176640000 -> 0000000122234466789 with missing 5, therefore A137580(20) = 9, a(21)=20;
21! = 51090942171709440000 -> 00000001112444577999 with missing {3,6,8}, therefore A137580(21) = 7, a(22)=21;
22! = 1124000727777607680000 -> 0000000011224667777778 with missing {5,7,9}, therefore A137580(22) = 7, a(23)=22;
23! = 25852016738884976640000 -> 00000122344556667788889 pandigital, A137580(23) = 10, 23 is not a term;
24! = 620448401733239439360000 -> 000000122333334444667899 with missing 5, therefore A137580(24) = 9, a(24)=24;
25! = 15511210043330985984000000 -> 00000000011112333445558899 with missing {6,7}, therefore A137580(24) = 8, a(25)=25.
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PROG
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(Haskell)
a182049 n = a182049_list !! (n-1)
a182049_list = filter ((< 10) . a137580) [0..]
(PARI) for(n=0, 999, #Set(digits(n!))<10&&print1(n", "))
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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STATUS
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approved
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