OFFSET
2,1
COMMENTS
It is well known that the variance of the Mahonian distribution is equal to sigma^2=n(n-1)(2n+5)/72. It is possible to have the asymptotic expansion for Kendell-Mann numbers M(n)=n!/sigma * 1/sqrt(2*Pi) * (1 - 2/(3*n) + O(1/n^2)). This results in M(n+1)/M(n)=n-1/2+O(1/n) as n--> infinity. [corrected by Vaclav Kotesovec, May 17 2015]
LINKS
Mikhail Gaichenkov, The property of Kendall-Mann numbers, answered by Richard Stanley, 2010
Mikhail Gaichenkov, A combinatorial proof for the property of KM numbers?
FORMULA
M(n) = Round(n!/sqrt(Pi*n(n-1)(2n+5)/36)).
EXAMPLE
M(2)=2, M(3)=3, M(4)=7,...
CROSSREFS
KEYWORD
nonn
AUTHOR
Mikhail Gaichenkov, Jan 30 2011
STATUS
approved