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A181609
Kendell-Mann numbers in terms of Mahonian distribution.
2
2, 3, 7, 23, 108, 604, 3980, 30186, 258969, 2479441, 26207604, 303119227, 3807956707, 51633582121, 751604592219, 11690365070546, 193492748067369, 3395655743755865, 62980031819261211, 1230967683216803500
OFFSET
2,1
COMMENTS
It is well known that the variance of the Mahonian distribution is equal to sigma^2=n(n-1)(2n+5)/72. It is possible to have the asymptotic expansion for Kendell-Mann numbers M(n)=n!/sigma * 1/sqrt(2*Pi) * (1 - 2/(3*n) + O(1/n^2)). This results in M(n+1)/M(n)=n-1/2+O(1/n) as n--> infinity. [corrected by Vaclav Kotesovec, May 17 2015]
LINKS
Mikhail Gaichenkov, The property of Kendall-Mann numbers, answered by Richard Stanley, 2010
FORMULA
M(n) = Round(n!/sqrt(Pi*n(n-1)(2n+5)/36)).
EXAMPLE
M(2)=2, M(3)=3, M(4)=7,...
CROSSREFS
Cf. A000140.
Sequence in context: A087164 A077213 A112601 * A205827 A098544 A176706
KEYWORD
nonn
AUTHOR
Mikhail Gaichenkov, Jan 30 2011
STATUS
approved