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A180417 a(n) = (A000111(2^n) - 1) / 2^n. 2

%I #19 Apr 19 2023 09:04:22

%S 0,0,1,173,1211969509,5547480986860602794895774677,

%T 708720364531529518355420122993246286974247836241724513772950684967495246261

%N a(n) = (A000111(2^n) - 1) / 2^n.

%C The definition yields integers according to the formula in A000111.

%C The next term a(7) is too large to include. - _N. J. A. Sloane_, Mar 14 2011

%H Alois P. Heinz, <a href="/A180417/b180417.txt">Table of n, a(n) for n = 0..8</a>

%t t = Range[0, 65]! CoefficientList[ Series[ Sec@x + Tan@x, {x, 0, 65}], x]; f[n_] := (Rest[t][[2^n]] - 1)/2^n; Array[f, 7, 0] (* _Robert G. Wilson v_, Sep 04 2010 *)

%o (Python)

%o from sympy import euler

%o def A180417(n): return euler(1<<n)-1>>n if n > 1 else 0 # _Chai Wah Wu_, Apr 18 2023

%Y Cf. A000079, A000111.

%K nonn

%O 0,4

%A _Vladimir Shevelev_, Sep 03 2010

%E Two more terms from _R. J. Mathar_, Sep 19 2010

%E a(5) and a(6) from _Robert G. Wilson v_, Sep 04 2010

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Last modified May 2 15:37 EDT 2024. Contains 372197 sequences. (Running on oeis4.)