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%I #2 Mar 30 2012 18:37:22
%S 0,1,0,-2,2,0,9,-4,3,0,-64,18,-6,4,0,620,-128,27,-8,5,0,-7536,1240,
%T -192,36,-10,6,0,109032,-15072,1860,-256,45,-12,7,0,-1809984,218064,
%U -22608,2480,-320,54,-14,8,0,33562944,-3619968,327096,-30144,3100,-384,63,-16
%N Matrix log of triangle A030528, where A030528(n,k) = C(k,n-k).
%F L(n,k) = (k+1)*L(n-k,0).
%F E.g.f. of column 0 satisfies: G(x) = (1+x)/(1+2*x)*G(x+x^2); more formulas given in A179199.
%e Triangle L begins:
%e 0;
%e 1,0;
%e -2,2,0;
%e 9,-4,3,0;
%e -64,18,-6,4,0;
%e 620,-128,27,-8,5,0;
%e -7536,1240,-192,36,-10,6,0;
%e 109032,-15072,1860,-256,45,-12,7,0;
%e -1809984,218064,-22608,2480,-320,54,-14,8,0;
%e 33562944,-3619968,327096,-30144,3100,-384,63,-16,9,0;
%e -681799680,67125888,-5429952,436128,-37680,3720,-448,72,-18,10,0;
%e 14980204800,-1363599360,100688832,-7239936,545160,-45216,4340,-512,81,-20,11,0; ...
%e where column_k = (k+1)*column_0: L(n,k) = (k+1)*L(n-k,0).
%o (PARI) {L(n,k)=local(A030528=matrix(n+1,n+1,r,c,if(r>=c,binomial(c,r-c))),LOG,ID=A030528^0); LOG=sum(m=1,n+1,-(ID-A030528)^m/m);(n-k)!*LOG[n+1,k+1]}
%Y Cf. A179199 (column 0), A179200, A179201, A030528.
%K sign
%O 0,4
%A _Paul D. Hanna_, Jul 09 2010
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