OFFSET
0,1
FORMULA
a(n) = 30^(2^(n-1)) + 1, n > 0.
a(n) = 2 + Product_{i=0..n-1} a(i).
a(n) = 1 + (a(n-1)-1)^2, n > 1.
Product_{n>=0} (1 - 1/a(n)) = 14/15. - Amiram Eldar, Dec 01 2025
MATHEMATICA
a[0] := 29;
a[n_] := a[n] = Product[a[i], {i, 0, n - 1}] + 2;
Table[a[n], {n, 0, 10}]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Roger L. Bagula, May 27 2010
EXTENSIONS
Edited by the Assoc. Eds. of the OEIS, Jul 20 2010
STATUS
approved
