OFFSET
1,3
COMMENTS
Probability that Fib(n) contains no 3's decreases to zero as n goes to infinity. I suppose that the maximum number is Fib(223) having 47 digits, none of them being a "3".
EXAMPLE
a(6)=21 since 21 is the 6th Fibonacci having no 3's.
MATHEMATICA
Join[{0}, Select[Fibonacci[Range[2, 60]], DigitCount[#, 10, 3]==0&]] (* Vincenzo Librandi, May 09 2019 *)
PROG
(Magma) [0] cat [Fibonacci(n): n in [2..150] | not 3 in Intseq(Fibonacci(n))]; // Vincenzo Librandi, May 09 2019
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Carmine Suriano, May 06 2010
EXTENSIONS
a(1) changed from 1 to 0 by Vincenzo Librandi, May 09 2019
STATUS
approved