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 A177001 The number of 3x+1 steps in the Collatz iteration of A033491(n), the least number requiring n iterations. 0
 0, 0, 0, 0, 1, 1, 2, 2, 2, 2, 2, 3, 3, 4, 4, 5, 5, 5, 6, 6, 6, 6, 7, 7, 7, 8, 8, 8, 9, 9, 9, 10, 10, 11, 11, 11, 11, 12, 12, 12, 13, 13, 13, 14, 14, 15, 15, 15, 16, 16, 16, 17, 17, 18, 18, 18, 18, 19, 19, 20, 20, 20, 21, 21, 22, 22, 23, 23, 24, 24, 24, 24, 25, 25, 25, 26, 26, 27, 27, 28 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,7 COMMENTS It appears that a(n) is the maximum number of 3x+1 steps for all numbers requiring n Collatz iterations, which is row n of A127824. LINKS Table of n, a(n) for n=1..80. FORMULA For large n, a(n) ~ n * log(2)/log(6). EXAMPLE 24 is the smallest number that requires 10 Collatz iterations. The iteration uses two 3x+1 steps to produce 24, 12, 6, 3, 10, 5, 16, 8, 4, 2, 1. Hence a(10)=2. MATHEMATICA col[n_] := NestWhileList[If[EvenQ[#], #/2, 3 # + 1] &, n, # > 1 &]; Table[k = 1; While[Length[(y = col[k])] - 1 != n, k++]; Count[y, _?OddQ] - 1, {n, 80}] (* Jayanta Basu, Jul 27 2013 *) CROSSREFS Sequence in context: A218379 A242763 A018119 * A143594 A298949 A329097 Adjacent sequences: A176998 A176999 A177000 * A177002 A177003 A177004 KEYWORD nonn AUTHOR T. D. Noe, Apr 30 2010 STATUS approved

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Last modified March 4 14:06 EST 2024. Contains 370532 sequences. (Running on oeis4.)