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A176175
Numbers k such that (2^(k-1) mod k) = number of prime divisors of k (counted with multiplicity).
1
1, 3, 5, 6, 7, 10, 11, 13, 14, 17, 19, 22, 23, 26, 29, 31, 34, 37, 38, 41, 43, 46, 47, 53, 58, 59, 61, 62, 67, 71, 73, 74, 79, 82, 83, 86, 89, 94, 97, 101, 103, 106, 107, 109, 113, 118, 122, 127, 131, 134, 137, 139, 142, 146, 149, 151, 157, 158, 163, 166, 167, 173, 178, 179, 181, 191, 193, 194, 197, 199, 202, 206, 211, 214, 218, 223, 226, 227, 229, 233, 239, 241, 251, 254
OFFSET
1,2
COMMENTS
How is this related to A085118? - R. J. Mathar, Jul 02 2025
FORMULA
{k: A001222(k) = A062173(k)}.
MAPLE
for n from 1 to 180 do modp(2^(n-1), n) ; if % = numtheory[bigomega](n) then printf("%d, ", n) ; end if; end do: # R. J. Mathar, Dec 07 2010
MATHEMATICA
Select[Range[254], PrimeOmega[#] == PowerMod[2, # - 1, #] &] (* Michael De Vlieger, Jul 02 2025 *)
CROSSREFS
Sequence in context: A281995 A304452 A292763 * A381241 A157201 A067351
KEYWORD
nonn
AUTHOR
STATUS
approved