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%I #8 Apr 26 2021 02:34:00
%S 1,1,1,1,5,1,1,85,85,1,1,21845,371365,21845,1,1,1431655765,
%T 6254904037285,6254904037285,1431655765,1,1,6148914691236517205,
%U 1760625833240390967011987365,452480839142780478522080752805,1760625833240390967011987365,6148914691236517205,1
%N Triangle T(n, k) = c(n)/(c(k)*c(n-k)) where c(n) = Product_{j=0..n} A051179(j), read by rows.
%H G. C. Greubel, <a href="/A173475/b173475.txt">Rows n = 0..10 of the triangle, flattened</a>
%F T(n, k) = c(n)/(c(k)*c(n-k)) where c(n) = Product_{j,0,n} A051179(j).
%e Triangle begins as:
%e 1;
%e 1, 1;
%e 1, 5, 1;
%e 1, 85, 85, 1;
%e 1, 21845, 371365, 21845, 1;
%e 1, 1431655765, 6254904037285, 6254904037285, 1431655765, 1;
%t c[n_]:= Product[2^(2^j) - 1, {j,0,n}];
%t T[n_, k_]:= c[n]/(c[k]*c[n-k]);
%t Table[T[n, k], {n,0,8}, {k,0,n}]//Flatten
%o (Sage)
%o @CachedFunction
%o def c(n): return product( 2^(2^j) -1 for j in (0..n) )
%o def T(n,k): return c(n)/(c(k)*c(n-k))
%o flatten([[T(n,k) for k in (0..n)] for n in (0..8)]) # _G. C. Greubel_, Apr 26 2021
%Y Cf. A051179.
%K nonn,tabl,less
%O 0,5
%A _Roger L. Bagula_, Feb 19 2010
%E Edited by _G. C. Greubel_, Apr 26 2021
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