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A168133
Numbers m = Sum_{k=1..n} sigma(k) such that Sum_{k=1..n} sigma(k) is divisible by k.
4
1, 4, 56, 99, 238, 3276, 26820, 55167, 550514, 3842258, 16222973, 56731455, 118396264, 396379039896, 9772829297132, 15876697439182, 2710103706735457, 4438313663247000, 12136546505785858, 3518811208764622050
OFFSET
1,2
COMMENTS
Numbers m = A024916(k) such that A024916(k) / k is an integer. If a(14) exists it must be bigger than 8*10^9.
Corresponding values of k, and sum_(k=1...n) sigma(k)/k are given in A056550 and A168132. - Jaroslav Krizek, Nov 21 2009
LINKS
EXAMPLE
Number a(3) = 56 = A024916(8) is in sequence because A024916(8) / 8 = 56 / 8 = 7 is an integer for k = 8.
CROSSREFS
KEYWORD
nonn
AUTHOR
Jaroslav Krizek, Nov 18 2009, Dec 04 2009
STATUS
approved