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A166926
A000004 preceded by 1, 2, 4.
6
1, 2, 4, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
OFFSET
0,2
COMMENTS
Inverse binomial transform of A058331.
FORMULA
a(0) = 1, a(1) = 2, a(2) = 4, a(n) = 0 for n > 2.
G.f.: (1+2*x+4*x^2).
a(n) = 2^n mod 8. - Ridouane Oudra, Apr 08 2025
PROG
(PARI) {concat([1, 2, 4], vector(102))}
CROSSREFS
Cf. A000004 (zero sequence), A058331 (2*n^2+1), A130706 (1, 2, 0, 0, 0, 0, ...), A130779 (1, 1, 2, 0, 0, 0, 0, ...).
Sequence in context: A082871 A321406 A383856 * A266296 A028573 A138758
KEYWORD
easy,nonn
AUTHOR
Klaus Brockhaus, Oct 23 2009
STATUS
approved