OFFSET
1,1
COMMENTS
Conjecture: pi((sqrt(P(n))+1)^2) - pi(P(n)) >= n.
MATHEMATICA
a[n_] := Product[Prime[k], {k, 1, n}]; Table[PrimePi[(Sqrt[a[n]] + 1)^2] - PrimePi[a[n]], {n, 1, 12}] (* G. C. Greubel, May 22 2016 *)
PROG
(PARI) a(n) = my(P=vecprod(primes(n))); primepi((sqrt(P)+1)^2) - primepi(P); \\ Michel Marcus, Aug 15 2022
CROSSREFS
KEYWORD
nonn,more,less
AUTHOR
Daniel Tisdale, Oct 18 2009, Oct 23 2009
EXTENSIONS
a(13)-a(15) from Ray Chandler, May 10 2010
Name edited by Michel Marcus, Aug 15 2022
STATUS
approved