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A165543
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Number of permutations of length n which avoid the patterns 3241 and 4321.
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2
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1, 1, 2, 6, 22, 89, 380, 1678, 7584, 34875, 162560, 766124, 3644066, 17469863, 84324840, 409471090, 1998933556, 9804748548, 48298256084, 238840150970, 1185256302910, 5900843531665, 29464355189120, 147522603762870, 740471407808372, 3725334547101464, 18782663124890072, 94889671255981134
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OFFSET
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0,3
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COMMENTS
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These permutations have an enumeration scheme of depth 4.
Conjecturally, a(n) is the number of permutations pi of length n such that s(pi) avoids the patterns 231 and 321, where s denotes West's stack-sorting map. - Colin Defant, Sep 17 2018
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LINKS
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FORMULA
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a(n) = sum(m=1..n-1, (m*sum(k=1..n-m, (k*binomial(m+2*k-1,m+k-1)*binomial(2*(n-m)-k-1,n-m-1))/(m+k)))/(n-m))+1. (End)
a(n) is the top left term in M^n, M = an infinite square production matrix with A000108 as the left column, as follows:
1, 1, 0, 0, 0, ...
1, 1, 1, 0, 0, ...
2, 1, 1, 1, 0, ...
5, 1, 1, 1, 1, ...
... (End)
a(n) ~ 2^(4*n + 3/2) / (25 * sqrt(Pi) * n^(3/2) * 3^(n - 3/2)). - Vaclav Kotesovec, Aug 14 2018
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EXAMPLE
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There are 22 permutations of length 4 which avoid these two patterns, so a(4)=22.
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MATHEMATICA
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a[0] = 1; a[n_] := Sum[ (m*Sum[ (k*Binomial[m+2*k-1, m+k-1]*Binomial[2*(n-m)-k-1, n-m-1])/(m + k), {k, 1, n-m}])/(n-m), {m, 1, n-1}] + 1; Table[a[n], {n, 0, 27}] (* Jean-François Alcover, Jun 25 2013 *) (* adapted by Vincenzo Librandi, May 14 2017 *)
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PROG
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(Maxima)
a(n):=if n=0 then 0 else sum((m*sum((k*binomial(m+2*k-1, m+k-1)*binomial(2*(n-m)-k-1, n-m-1))/(m+k), k, 1, n-m))/(n-m), m, 1, n-1)+1; /* Vladimir Kruchinin, May 12 2011 */
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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