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 A165340 Triangle read by rows: T(n,0) = smallest number m such that A165331(m)=n and A165330(m)=153; T(n,k+1) = sum of cubes of digits of T(n,k), 0<=k
 153, 135, 153, 18, 513, 153, 3, 27, 351, 153, 9, 729, 1080, 513, 153, 12, 9, 729, 1080, 513, 153, 33, 54, 189, 1242, 81, 513, 153, 114, 66, 432, 99, 1458, 702, 351, 153, 78, 855, 762, 567, 684, 792, 1080, 513, 153, 126, 225, 141, 66, 432, 99, 1458, 702, 351 (list; table; graph; refs; listen; history; text; internal format)
 OFFSET 0,1 COMMENTS T(n,k+1) = A055012(T(n,k)), 0 <= k < n; A165331(T(n,k)) = n - k; A165330(T(n,k)) = 153; T(n,n) = 153; 10^10 < T(15,0) <= 22222599999999999999999, T(14,0) = 12558 = A055012(22222599999999999999999). LINKS R. Zumkeller, Rows 0 to 14 of the triangle, flattened. EXAMPLE The triangle begins: n=0: 153, n=1: 135 -> 1+3^3+5^3=153, n=2: 18 -> 1+8^3=513 -> 5^3+1+3^3=153, n=3: 3 -> 3^3=27 -> 2^3+7^3=351 -> 3^3+5^3+1=153, n=4: 9 -> 9^3=729 -> 7^3+2^3+9^3=1080 -> 1+0+8^3+0=513 -> 5^3+1+3^3=153, n=5: 12 -> 1+2^3=9 -> 9^3=729 -> 7^3+2^3+9^3=1080 -> 1+0+8^3+0=513 -> 5^3+1+3^3=153, n=6: 33 -> 2*3^3=54 -> 5^3+4^3=189 -> 1+8^3+9^3=1242 -> 1+2^3+4^3+2^3=81 -> 8^3+1=513 -> 5^3+1+3^3=153. CROSSREFS Sequence in context: A156740 A095226 A346630 * A183985 A184045 A203603 Adjacent sequences: A165337 A165338 A165339 * A165341 A165342 A165343 KEYWORD base,nonn,tabl AUTHOR Reinhard Zumkeller, Sep 17 2009 STATUS approved

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Last modified March 27 22:47 EDT 2023. Contains 361575 sequences. (Running on oeis4.)