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%I #6 Nov 09 2019 01:18:07
%S 1,10,10,11,11,11,10,11,100,100,101,11,11,100,101,100,101,101,11,100,
%T 11,101,100,100,11,100,101,101,101,100,111,11,11,100,100,101,101,100,
%U 101,101,101,101,111,11,100,101,101,111,101,101,101,111,101,111,10
%N A014499 represented in binary.
%H Andrew Howroyd, <a href="/A162720/b162720.txt">Table of n, a(n) for n = 1..1000</a>
%F a(n) = A007088(A014499(n)). - _Andrew Howroyd_, Nov 08 2019
%e The 5th prime number is 11. The binary representation of 11 is 1011. There are 3 "1s" in 1011. 3 in binary is 11, so a(5)=3.
%o (PARI) a(n)={fromdigits(digits(hammingweight(prime(n)), 2))} \\ _Andrew Howroyd_, Nov 08 2019
%Y Cf. A007088, A014499.
%K base,nonn
%O 1,2
%A _Ben Branman_, Jul 11 2009
%E Terms a(32) and beyond from _Andrew Howroyd_, Nov 08 2019