OFFSET
3,1
COMMENTS
10(b2) and 31(b5) do not both halve and double by rotations. No 2-digit answer can meet the description, so the sequence begins with a base 3 value.
LINKS
W. A. Hoffman III, Algorithm to compute terms.
EXAMPLE
1042(b8)/2 = 421(b8) and 1042(b8)*2 = 2104(b8)
316 (base 11) = 380 (base 10), 163 (base 11) = 190 (base 10), 631 (base 11) = 760 (base 10).
CROSSREFS
KEYWORD
base,nonn,fini,full
AUTHOR
William A. Hoffman III (whoff(AT)robill.com), Apr 21 2009
EXTENSIONS
Offset corrected by N. J. A. Sloane, Apr 23 2009
a(11) corrected. To indicate that terms from base n=13 on need digits larger than 9, keywords fini, full added. - Ray Chandler and R. J. Mathar, Apr 23 2009
Edited by Ray Chandler, May 02 2009
STATUS
approved