A156083 In this sequence each prime ends a prime century. Place a 0 between the final two digits, and raise the 100s digit by 1, to form the first prime of the next century.

8783, 22787, 23899, 26893, 37897, 54679, 64891, 65789, 67891, 70891, 71899, 73897, 76781, 89899, 91781, 98899, 108677, 110899, 115891, 124897, 130787, 131899, 133781, 139891, 144671, 149899, 152899, 164789, 187897, 190891, 206783, 207679

Offset

1,1

Comments

These appear to occur in a fairly random fashion much like prime quadruplets.

The 10s digit must be greater by 1 than the 100s digit. - Tanya Khovanova, Jul 10 2021

Links

Charles R Greathouse IV, Table of n, a(n) for n = 1..10000

Example

8783 becomes 8803, note that 83 becomes 803.

Prog

(PARI) is(p)=my(q=nextprime(p+1), a=p%1000\100); isprime(p) && a==p%100\10-1 && q-p==90-10*a \\ Charles R Greathouse IV, Feb 07 2013

Crossrefs

Sequence in context: A255758 A255751 A254840 * A249956 A031791 A389390

Adjacent sequences: A156080 A156081 A156082 * A156084 A156085 A156086

Keyword

nonn,base

Author

Ki Punches, Feb 03 2009, Feb 08 2009

Extensions

Corrected and extended by Ki Punches, Feb 08 2009

a(22) and a(32) corrected by Charles R Greathouse IV, Feb 07 2013

Status

approved