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%I #2 Mar 31 2012 13:21:05
%S 1,1,1,1,2,4,19,21,28,151,200,709,767,5727,15908,162819,302991
%N Greatest number m such that the fractional part of (11/10)^A153687(m) >= 1-(1/m).
%F a(n):=floor(1/(1-fract((11/10)^A153687(n)))), where fract(x) = x-floor(x).
%e a(6)=4, since 1-(1/5)=0.8>fract((11/10)^A153687(6))=fract((11/10)^6)=0.771...>=1-(1/4).
%Y Cf. A153663, A153671, A153679, A153683, A154130, A153699, A153707, A153715, A153723.
%K nonn,more
%O 1,5
%A _Hieronymus Fischer_, Jan 06 2009
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