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A153428
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Numbers n such that phi(n) = p^3, where p is product of digits of n.
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3
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1, 14611, 141152, 2831112, 113216152, 419521121, 5342121213, 7112216125, 11191442171, 11371542112, 12192256111, 12327134121, 12432712113, 13161313512, 14132133215, 113335111416, 127131142512, 133412214117, 196112145112, 311721152134, 312118111536, 312127213125, 322631161151, 411111553831, 432122133312
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OFFSET
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1,2
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LINKS
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EXAMPLE
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phi(113216152) = (1*1*3*2*1*6*1*5*2)^3, so 113216152 is in the sequence.
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MATHEMATICA
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Do[If[Apply[Times, IntegerDigits[n]]^3==EulerPhi[n], Print[n]], {n, 300000000}]
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CROSSREFS
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KEYWORD
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base,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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