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A152836
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a(0)=-1; a(n)=n^a(n-1)-a(n-1)^n.
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5
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OFFSET
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0,2
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COMMENTS
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Sequence is finite because followup terms are fractions. - R. J. Mathar, Jun 19 2021
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LINKS
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MATHEMATICA
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lst={}; a=1; Do[a=n^a-a^n; AppendTo[lst, a], {n, 0, 5}]; lst
nxt[{n_, a_}]:={n+1, (n+1)^a-a^(n+1)}; NestList[nxt, {0, -1}, 5][[All, 2]] (* Harvey P. Dale, Jun 06 2022 *)
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CROSSREFS
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KEYWORD
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sign,fini,less
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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