|
|
A152390
|
|
Arises in enumerating non-degenerate colorings in Brook's Theorem.
|
|
0
|
|
|
6, 68, 252, 648, 1370, 2556, 4368, 6992, 10638, 15540, 21956, 30168, 40482, 53228, 68760, 87456, 109718, 135972, 166668, 202280, 243306, 290268, 343712, 404208, 472350, 548756, 634068, 728952, 834098, 950220, 1078056, 1218368, 1371942
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,1
|
|
COMMENTS
|
Gravin's abstract: Let c => 2 and p => c be two integers. We will call a proper coloring of the graph G a (c,p)-nondegenerate, if for any vertex of G with degree at least p there are at least c vertices of different colors adjacent to it. In our work we prove the following result, which generalizes Brook's Theorem. Let D => 3 and G be a graph without cliques on D+1 vertices and the degree of any vertex in this graph is not greater than D. Then for every integer c => 2 there is a proper (c,p)-nondegenerate vertex D-coloring of G, where p=(c^3+8c^2+19c+6)(c+1). During the primary proof, some interesting corollaries are derived.
|
|
LINKS
|
|
|
FORMULA
|
a(n) = (n^3+8*n^2+19*n+6)*(n+1).
G.f.: 2(3+19x-14x^2+4x^3)/(1-x)^5. [From R. J. Mathar, Dec 04 2008]
|
|
EXAMPLE
|
a(2) = 252 because ((2^3) + (8 * (2^2)) + (19 * 2) + 6) * (2 + 1) = 252.
|
|
MATHEMATICA
|
LinearRecurrence[{5, -10, 10, -5, 1}, {6, 68, 252, 648, 1370}, 50] (* Harvey P. Dale, Jan 29 2023 *)
|
|
CROSSREFS
|
|
|
KEYWORD
|
easy,nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|