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A146362 Primes p such that continued fraction of (1+Sqrt[p])/2 has period 17 : primes in A146340. 1
521, 617, 709, 1433, 1597, 2549, 2909, 3581, 3821, 4013, 4649, 5501, 5693, 5813, 6197, 7853, 8093, 8573, 9281, 9677, 10597, 10973, 11273, 13109, 13613, 15413, 15641, 15737, 16001, 16477, 17093, 20261 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

LINKS

Table of n, a(n) for n=1..32.

MATHEMATICA

$MaxExtraPrecision = 4000; s = 10; aa = {}; Do[k = ContinuedFraction[(1 + Sqrt[Prime[n]])/2, 3000]; m = 1; While[k[[s]] != k[[s + m]] || k[[s + m]] != k[[s + 2 m]] || k[[s + 2 m]] != k[[s + 3 m]] || k[[s + 3 m]] != k[[s + 4 m]] || k[[s + 4 m]] != k[[s + 5 m]], m++ ]; s = s + 1; While[k[[s]] != k[[s + m]] || k[[s + m]] != k[[s + 2 m]] || k[[s + 2 m]] != k[[s + 3 m]] || k[[s + 3 m]] != k[[s + 4 m]] || k[[s + 4 m]] != k[[s + 5 m]], m++ ]; s = s + 1; While[k[[s]] != k[[s + m]] || k[[s + m]] != k[[s + 2 m]] || k[[s + 2 m]] != k[[s + 3 m]] || k[[s + 3 m]] != k[[s + 4 m]] || k[[s + 4 m]] != k[[s + 5 m]]; AppendTo[aa, m]], {n, 1, 1495}]; bb = {}; Do[If[aa[[n]] == 17, AppendTo[bb, Prime[n]]], {n, 1, Length[aa]}]; bb (*Artur Jasinski*)

CROSSREFS

A000290, A050950-A050969, A078370, A146326-A146345, A146348-A146360.

Sequence in context: A300395 A139663 A146340 * A050966 A113158 A004928

Adjacent sequences:  A146359 A146360 A146361 * A146363 A146364 A146365

KEYWORD

nonn

AUTHOR

Artur Jasinski, Oct 30 2008

EXTENSIONS

Period length in definition corrected, 2579, 5003 removed, 5813 inserted by R. J. Mathar, Sep 06 2009

STATUS

approved

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Last modified December 12 09:36 EST 2019. Contains 329953 sequences. (Running on oeis4.)