OFFSET
1,10
COMMENTS
Sum of n-th row terms = rightmost term in next row.
The INVERTi transform of A000009 starting with offset 1 = (1, 0, 1, -1, -1, 1, -2, 2, -2, 2, -3, 3, -3, 4, -5, 5, -5, 6,...); i.e. A000700 signed = left border.
A000700 is derived from parity changes of A000041 as follows: Given A000041: (1, 1, 2, 3, 5, 7, 11, 15, 22, 30, 42, 56, 77, 101, 135,...). Write down the parity starting (1, 1, 0, 1, 1, 1, 1, 1...) then add "1" starting in the next string of A000041 with a change in parity. Since the next 4 terms of A000041 are (22, 30, 42, 56...) we denote these by (...2, 2, 2, 2...). The next three p(n) terms are 77, 101, 135, so these are (...3, 3, 3,...) in A000700.
FORMULA
EXAMPLE
First few rows of the triangle =
1;
0, 1;
1, 0, 1;
-1, 1, 0, 2;
1, -1, 1, 0, 2;
-1, 1, -1, 2, 0, 3;
1, -1, 1, -2, 2, 0, 4;
-2, 1, -1, 2, -2, 3, 0, 5;
2, -2, 1, -2, 2, -3, 4, 0, 6;
-2, 2, -2, 2, -2, 3, -4, 5, 0, 8;
2, -2, 2, -4, 2, -3, 4, -5, 6, 0, 10;
-3, 2, -2, 4, -4, 3, -4, 5, -6, 8, 0, 12;
3, -3, 2, -4, 4, -6, 4, -5, 6, -8, 10, 0, 15;
-3, 3, -3, 4, -4, 6, -8, 5, -6, 8, -10, 12, 0, 18;
4, -3, 3, -6, 4, -6, 8, -10, 6, -8, 10, -12, 15, 0, 22;
-5, 4, -3, 6, -6, 6, -8, 10, -12, 8, -10, 12, -15, 18, 0, 27;
5, -5, 4, -6, 6, -9, 8, -10, 12, -16, 10, -12, 15, -18, 22, 0, 32;
...
CROSSREFS
KEYWORD
tabl,sign
AUTHOR
Gary W. Adamson, Oct 26 2008
STATUS
approved