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A141384
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Trace of the n-th power of a certain 8X8 adjacency matrix.
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2
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8, 8, 32, 158, 828, 4408, 23564, 126106, 675076, 3614144, 19349432, 103593806, 554625900, 2969386480, 15897666068, 85113810058, 455687062276, 2439682811480, 13061709929936, 69930511268510, 374397872321628
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OFFSET
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0,1
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COMMENTS
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a(n) is the trace of the n-th power of the adjacency matrix of order 8 whose rows are (up to simultaneous permutations of the rows and columns): 10111010 01111001 01111001 10111010 00111000 11111111 11111111 11111111.
For n>2, this is also the number of ways to mark one edge at every vertex of a regular n-gonal prism so that no edge is marked at both extremities.
Remarkably, for n>1, a(n)=A141221(n)+2.
The fourth-order linear recurrence established by Max Alekseyev for A141221, based on the minimal polynomial of the above (singular) matrix, namely x(x-1)(x^3-7x^2+9x-1) = x^5-8*x^4+16*x^3-10*x^2+x. Since its degree is 5, the corresponding recurrence holds for corresponding elements of the successive powers (or sums thereof, including matrix traces) only for n>=5. The recurrence would be valid down to n=4 if we had a(0)=4, which is not the case.
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LINKS
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FORMULA
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For n>=5, a(n) = 8*a(n-1)-16*a(n-2)+10*a(n-3)-a(n-4).
For positive values of n: a(n) = (5.3538557854308)^n + (1.5235479602692)^n + 1 + (0.1225962542999)^n. The dominant term in the above is the n-th power of (7+2*sqrt(22)*cos(atan(sqrt(5319)/73)/3))/3.
G.f.: 2*(4-28*x+48*x^2-25*x^3+2*x^4)/((1-x)*(1-7*x+9*x^2-x^3)). [Colin Barker, Jan 20 2012]
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EXAMPLE
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a(0) = 8 because the trace of the order-8 identity matrix is 8.
a(1) = 8 because all diagonal elements of the adjacency matrix are 1 (there's a loop at each vertex).
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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