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%I #41 Nov 17 2024 10:12:38
%S 0,8,20,36,56,80,108,140,176,216,260,308,360,416,476,540,608,680,756,
%T 836,920,1008,1100,1196,1296,1400,1508,1620,1736,1856,1980,2108,2240,
%U 2376,2516,2660,2808,2960,3116,3276,3440,3608,3780,3956,4136,4320,4508,4700,4896
%N a(n) = 2*n*(n+3).
%C Numbers n such that 2*n + 9 is a square. - _Vincenzo Librandi_, Nov 24 2010
%C a(n) appears also as the fourth member of the quartet [p0(n), p1(n), p2(n), a(n)] of the square of [n, n+1, n+2, n+3] in the Clifford algebra Cl_2 for n >= 0. p0(n) = -A147973(n+3), p1(n) = A046092(n), and p2(n) = A054000(n+1). See a comment on A147973, also with a reference. - _Wolfdieter Lang_, Oct 15 2014
%H Vincenzo Librandi, <a href="/A139570/b139570.txt">Table of n, a(n) for n = 0..1000</a>
%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (3,-3,1).
%F a(n) = 2*A028552(n) = 2*n^2 + 6*n = n*(2*n+6).
%F a(n) = a(n-1) + 4*n + 4 (with a(0)=0). - _Vincenzo Librandi_, Nov 24 2010
%F From _Paul Curtz_, Mar 27 2011: (Start)
%F a(n) = A022998(n)*A022998(n+3).
%F a(n) = 4*A000096(n). (End)
%F G.f.: 4*x*(2 - x)/(1 - x)^3. - _Arkadiusz Wesolowski_, Dec 31 2011
%F From _Amiram Eldar_, Dec 23 2022: (Start)
%F Sum_{n>=1} 1/a(n) = 11/36.
%F Sum_{n>=1} (-1)^(n+1)/a(n) = log(2)/3 - 5/36. (End)
%F From _Elmo R. Oliveira_, Nov 16 2024: (Start)
%F E.g.f.: 2*exp(x)*x*(4 + x).
%F a(n) = n*A020739(n).
%F a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) for n > 2. (End)
%t CoefficientList[Series[4 x (2 - x)/(1 - x)^3, {x, 0, 40}], x] (* _Vincenzo Librandi_, May 23 2014 *)
%o (PARI) a(n)=2*n*(n+3) \\ _Charles R Greathouse IV_, Jun 17 2017
%Y Cf. A000096, A001105, A020739, A022998, A028552, A046092, A054000, A067728, A147973.
%K easy,nonn
%O 0,2
%A _Omar E. Pol_, May 19 2008