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A138912
Inverse binomial transform of A138911.
1
1, 1, 2, 9, 28, 145, 726, 4249, 27000, 186561, 1387450, 11034001, 93295236, 834720913, 7870851366, 77943848025, 808159323376, 8749874083585, 98687599614450, 1157060036429857, 14075106913366140, 177337182574590801
OFFSET
0,3
COMMENTS
The n-th term of the n-th inverse binomial transform of A138911 is 1 for n>=0.
FORMULA
O.g.f. satisfies: [x^n] A( x/(1+(n-1)*x) )/(1+(n-1)*x) = 1 for n>=0.
E.g.f. satisfies: [x^n] A(x)*exp(-(n-1)*x) = 1/n! for n>=0.
PROG
(PARI) {a(n)=local(A=[1]); for(k=1, n, A=concat(A, 0); A[k+1]=1-polcoeff(subst(Ser(A), x, x/(1+(k-1)*x+x*O(x^k)))/(1+(k-1)*x), k)); A[n+1]}
CROSSREFS
Cf. A138911 (binomial transform).
Sequence in context: A291632 A328281 A324372 * A374827 A002747 A110377
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Apr 05 2008
STATUS
approved