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A137391
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Triangle: let f(t) = 1 + t + t^2 and g(t) = t + t^2, expansion of p(t) = f(t)*exp(x*g(t)).
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0
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1, 1, 1, 2, 4, 1, 0, 12, 9, 1, 0, 24, 48, 16, 1, 0, 0, 180, 140, 25, 1, 0, 0, 360, 840, 330, 36, 1, 0, 0, 0, 3360, 2940, 672, 49, 1, 0, 0, 0, 6720, 18480, 8400, 1232, 64, 1, 0, 0, 0, 0, 75600, 75600, 20664, 2088, 81, 1, 0, 0, 0, 0, 151200, 483840, 252000, 45360, 3330
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OFFSET
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1,4
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LINKS
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EXAMPLE
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{1},
{1, 1},
{2, 4, 1},
{0, 12, 9, 1},
{0, 24, 48, 16, 1},
{0, 0, 180, 140, 25, 1},
{0, 0, 360, 840, 330, 36, 1},
{0, 0, 0, 3360, 2940, 672, 49, 1},
{0, 0, 0, 6720, 18480, 8400, 1232, 64, 1},
{0, 0, 0, 0, 75600, 75600, 20664, 2088, 81, 1},
{0, 0, 0, 0, 151200, 483840, 252000, 45360, 3330, 100, 1}
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MATHEMATICA
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f[t_] = 1 + t + t^2;
g[t_] = t + t^2;
p[t_] = f[t]*Exp[x*g[t]];
Table[ ExpandAll[n!*SeriesCoefficient[ Series[p[t], {t, 0, 30}], n]], {n, 0, 10}];
a = Table[ CoefficientList[n!*SeriesCoefficient[ Series[p[t], {t, 0, 30}], n], x], {n, 0, 10}];
Flatten[a]
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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