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%I #2 Sep 24 2013 00:41:43
%S 1,1,1,3,1,1,1,2,2,1,1,1,4,4,1,1,3,1,3,4,6,4,1,4,6,1,4,1,4,6,5,6,8,3,
%T 2,6,6,2,8,1,7,2,8,1,1,7,9,1,8,2,1,3,2,1,8,4,4,5,1,2,3,2,4,2,5,8,1,2,
%U 3,8,8,2,2,1,4,1,5,5,5,4,2,8,5,8,4,4,5,3,8,4,1,2,6,8,9,4,1,8,3,8,4,4,4,3,1
%N Length of the cycles in which finish the sequences a(k+1)=sopfr(n a(k)), with sopfr=A001414.
%C Similar to A136140 or to A136147, now with D=0.
%p see A136140
%Y Cf. A136140, A136147.
%K nonn
%O 0,4
%A _Carlos Alves_, Dec 16 2007