login
A136148
Length of the cycles in which finish the sequences a(k+1)=sopfr(n a(k)), with sopfr=A001414.
1
1, 1, 1, 3, 1, 1, 1, 2, 2, 1, 1, 1, 4, 4, 1, 1, 3, 1, 3, 4, 6, 4, 1, 4, 6, 1, 4, 1, 4, 6, 5, 6, 8, 3, 2, 6, 6, 2, 8, 1, 7, 2, 8, 1, 1, 7, 9, 1, 8, 2, 1, 3, 2, 1, 8, 4, 4, 5, 1, 2, 3, 2, 4, 2, 5, 8, 1, 2, 3, 8, 8, 2, 2, 1, 4, 1, 5, 5, 5, 4, 2, 8, 5, 8, 4, 4, 5, 3, 8, 4, 1, 2, 6, 8, 9, 4, 1, 8, 3, 8, 4, 4, 4, 3, 1
OFFSET
0,4
COMMENTS
Similar to A136140 or to A136147, now with D=0.
MAPLE
CROSSREFS
Sequence in context: A065372 A015137 A368202 * A178252 A338199 A325498
KEYWORD
nonn
AUTHOR
Carlos Alves, Dec 16 2007
STATUS
approved