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a(n) = A063882(n+1) - A063882(n).
1

%I #7 Jun 04 2021 16:39:59

%S 0,0,0,1,1,1,1,0,1,0,1,1,0,1,0,1,1,0,0,1,0,1,1,0,1,0,1,1,0,0,1,0,1,1,

%T 0,1,0,1,0,0,1,0,1,1,0,1,0,1,0,1,1,0,0,1,0,1,1,0,1,0,1,0,0,1,0,1,1,0,

%U 1,0,1,0,1,1,0,0,1,0,1,0,1,0,0,1,0,1,1,0,1,0,1,0,1,1,0,0,1,0,1,0,1,1,0,1,0

%N a(n) = A063882(n+1) - A063882(n).

%C 0 <= a(n) <= 1; 1 <= a(n)+a(n+1)+a(n+2) <= 2 for n>5.

%H B. Balamohan, A. Kuznetsov and S. Tanny, <a href="http://www.cs.uwaterloo.ca/journals/JIS/VOL10/Tanny/tanny3.html">On the behavior of a variant of Hofstadter's Q-sequence, JIS, Vol. 10 (2007), #07.7.1</a>

%Y Cf. A063882.

%K nonn

%O 1,1

%A _Reinhard Zumkeller_, Dec 11 2007