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A135419
Array read by rows, showing the ways of splitting the numbers from 1 to 16 into two groups so that the numbers in each group have the same sum (68) and the same sum of squares (748).
2
1, 2, 3, 4, 7, 10, 12, 13, 16, 1, 2, 3, 4, 8, 9, 11, 14, 16, 1, 2, 3, 5, 6, 10, 11, 14, 16, 1, 2, 3, 5, 7, 8, 12, 14, 16, 1, 2, 4, 5, 6, 8, 11, 15, 16, 1, 2, 7, 8, 11, 12, 13, 14, 1, 3, 6, 8, 10, 12, 13, 15, 1, 3, 6, 9, 10, 11, 12, 16, 1, 4, 5, 8, 10, 11, 14, 15, 1, 4, 6, 7, 9, 12, 14, 15, 1, 4, 6, 7, 10, 11, 13, 16, 1, 5, 6, 7, 8, 11, 14, 16
OFFSET
1,2
EXAMPLE
There are exactly 657 ways of splitting the numbers 1..16 into two groups so that the numbers in each group have the same sum s1=68.
There are exactly 57 ways of splitting the numbers 1..16 into two groups so that the numbers in each group have the same sum of squares s2=748.
And there is the only one way of splitting the numbers 1..16 into two groups so that the numbers in each group have the same sum of cubes s3=9248: {{1, 4, 6, 7, 10, 11, 13, 16} (=A133483) and {2, 3, 5, 8, 9, 12, 14, 15} (=A133484)}.
Amazingly, this last way also appears in previous two cases! This is given in A133483 and A133484.
(Also, there is the only one way of splitting the numbers 1..16 into two groups so that the numbers in each group have the same sum of fourth powers s4=121924: {{1,2,3,4,8,9,10,11,12,16},{5,6,7,13,14,15}}. But this splitting does not give equal sum of powers 1..3.)
Intersection of first two cases gives 12 ways of splitting the numbers 1..16 into two groups so that the numbers in each group have the same sum s1=68 and the same sum of squares s2=748;
Here we list only groups containing 1 (the corresponding 2nd groups are their complements):
{1,2,3,4,8,9,11,14,16},
{1,2,3,5,6,10,11,14,16},
{1,2,3,5,7,8,12,14,16},
{1,2,4,5,6,8,11,15,16},
{1,2,7,8,11,12,13,14},
{1,3,6,8,10,12,13,15},
{1,3,6,9,10,11,12,16},
{1,4,5,8,10,11,14,15},
{1,4,6,7,9,12,14,15},
{1,4,6,7,10,11,13,16},
{1,5,6,7,8,11,14,16}.
This table read by rows gives the present sequence.
CROSSREFS
KEYWORD
fini,full,nonn,tabf
AUTHOR
Zak Seidov, Dec 01 2007
EXTENSIONS
Error in example lines corrected by Colm Mulcahy, Dec 30 2007
STATUS
approved