OFFSET
1,1
COMMENTS
Let q = 1 + a(n)*2^n. Then q is least prime such that A098006(pi(q)) = 2^(n-1). See A134854 for the values of q.
a(n) = prime(k) for some k < 5*n for n <= 10000 . - Pierre CAMI, Jul 20 2014
LINKS
Pierre CAMI, Table of n, a(n) for n = 1..10000 (First 1000 terms from T. D. Noe)
MATHEMATICA
Table[Select[Prime[Range[2, 10000]], PrimeQ[1+2^k # ]&, 1][[1]], {k, 100}]
lop[n_]:=Module[{k=3, c=2^n}, While[!PrimeQ[1+k*c], k=NextPrime[k]]; k]; Array[ lop, 80] (* Harvey P. Dale, Sep 01 2022 *)
PROG
(PARI) a(n) = p=3; t=2^n; while(!isprime(1+p*t), p=nextprime(p+1)); p \\ Colin Barker, Jul 22 2014
CROSSREFS
KEYWORD
nonn
AUTHOR
T. D. Noe, Nov 13 2007
STATUS
approved