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A133899
Numbers m such that binomial(m+9,m) mod 9 = 0.
0
72, 73, 74, 75, 76, 77, 78, 79, 80, 153, 154, 155, 156, 157, 158, 159, 160, 161, 234, 235, 236, 237, 238, 239, 240, 241, 242, 315, 316, 317, 318, 319, 320, 321, 322, 323, 396, 397, 398, 399, 400, 401, 402, 403, 404, 477, 478, 479, 480, 481, 482, 483, 484, 485
OFFSET
0,1
COMMENTS
Also numbers m such that floor(1+(m/9)) mod 9 = 0.
Partial sums of the sequence 72,1,1,1,1,1,1,1,1,73,1,1,1,1,1,1,1,1,73, ... which has period 9.
FORMULA
a(n)=9n+72-8*(n mod 9).
G.f.: g(x)=(72+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9)/((1-x^9)(1-x)).
G.f.: g(x)=(72-71x-x^10) /((1-x^9)(1-x)^2).
MATHEMATICA
Select[Range[500], Divisible[Binomial[#+9, #], 9]&] (* Harvey P. Dale, Apr 03 2011 *)
KEYWORD
nonn
AUTHOR
Hieronymus Fischer, Oct 20 2007
STATUS
approved