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A132789
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Triangle read by rows: T(n,k) = A007318(n-1, k-1) + A001263(n, k) - 1.
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2
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1, 1, 1, 1, 4, 1, 1, 8, 8, 1, 1, 13, 25, 13, 1, 1, 19, 59, 59, 19, 1, 1, 26, 119, 194, 119, 26, 1, 1, 34, 216, 524, 524, 216, 34, 1, 1, 43, 363, 1231, 1833, 1231, 363, 43, 1, 1, 53, 575, 2603, 5417, 5417, 2603, 575, 53, 1, 1, 64, 869, 5069, 14069, 19655, 14069, 5069, 869
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OFFSET
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1,5
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LINKS
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FORMULA
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A symmetrical triangle recursion: let q=4; t(n,m,0)=Binomial[n,m]; t(n,m,1)=Narayana(n,m); t(n,m,2)=Eulerian(n+1,m); t(n,m,q)=t(n,m,g-2)+t(n,m,q-3).
T(n,k) = binomial(n-1, k-1)*(1 + binomial(n, k-1)/k) - 1. - Andrew Howroyd, Sep 08 2018
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EXAMPLE
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First few rows of the triangle are:
1;
1, 1;
1, 4, 1;
1, 8, 8, 1;
1, 13, 25, 13, 1;
1, 19, 59, 59, 19, 1;
1, 26, 119, 194, 119, 26, 1;
1, 34, 216, 524, 524, 216, 34, 1;
1, 43, 363, 1231, 1833, 1231, 363, 43, 1;
1, 53, 575, 2603, 5417, 5417, 2603, 575, 53, 1;
1, 64, 869, 5069, 14069, 19655, 14069, 5069, 869, 64, 1;
...
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MATHEMATICA
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<< DiscreteMath`Combinatorica`
t[n_, m_, 0] := Binomial[n, m];
t[n_, m_, 1] := Binomial[n, m]*Binomial[n + 1, m]/(m + 1);
t[n_, m_, 2] := Eulerian[1 + n, m];
t[n_, m_, q_] := t[n, m, q] = t[n, m, q - 2] + t[n, m, q - 3] - 1;
Table[Flatten[Table[Table[t[n, m, q], {m, 0, n}], {n, 0, 10}]], {q, 0, 10}]
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PROG
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(PARI) T(n, k)={if(k<=n, binomial(n-1, k-1)*(1 + binomial(n, k-1)/k) - 1, 0)}
for(n=1, 10, for(k=1, n, print1(T(n, k), ", ")); print); \\ Andrew Howroyd, Sep 08 2018
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CROSSREFS
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KEYWORD
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AUTHOR
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EXTENSIONS
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More terms, Mma program and additional comments from Roger L. Bagula, Apr 20 2010
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STATUS
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approved
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