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 A132341 Main diagonal of A132339. 2
 1, 2, 10, 168, 4290, 136136, 4938024, 196125600, 8318177010, 370784099400, 17184867259560, 821870841735840, 40334204896057800, 2022686389717666848, 103312949950998743200, 5360873347802169267840, 282015983963437605168210 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,2 LINKS G. C. Greubel, Table of n, a(n) for n = 0..500 G. Kreweras, Sur une classe de problèmes de dénombrement liés au treillis des partitions des entiers, Cahiers du Bureau Universitaire de Recherche Opérationnelle}, Institut de Statistique, Université de Paris, 6 (1965), see equation (67) circa p. 82. FORMULA a(n) = T(n, n), where T(n,k) if the array of A132339. a(n) = A(2*n, n), where A(n, k) is the antidiagonal triangle of A132339. a(n) ~ 2^(6*n - 9/2) / (Pi*n^3). - Vaclav Kotesovec, Mar 27 2016 a(n) = binomial(2*n, n)*binomial(4*n-2, 2*n-1)/((2*n)*(2*n-1)), with a(0) = 1. - G. C. Greubel, Dec 14 2021 MATHEMATICA a[n_]:= If[n==0, 1, Binomial[2*n, n]*Binomial[4*n-2, 2*n-1]/(2*Binomial[2*n, 2])]; Table[a[n], {n, 0, 20}] (* G. C. Greubel, Dec 14 2021 *) PROG (PARI) a(n) = if (n, 2*(4*n-3)!/(n!^2*(2*n-1)!), 1); \\ Michel Marcus, Mar 27 2016 (Sage) b=binomial def a(n): return 1 if (n==0) else b(2*n, n)*b(4*n-2, 2*n-1)/(2*b(2*n, 2)) [a(n) for n in (0..20)] # G. C. Greubel, Dec 14 2021 CROSSREFS Cf. A132339. Sequence in context: A328812 A126451 A260122 * A069994 A063573 A086675 Adjacent sequences:  A132338 A132339 A132340 * A132342 A132343 A132344 KEYWORD nonn,easy AUTHOR N. J. A. Sloane, Nov 08 2007 EXTENSIONS More terms from Max Alekseyev, Sep 12 2009 STATUS approved

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Last modified August 7 23:50 EDT 2022. Contains 355995 sequences. (Running on oeis4.)