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A125194 Numerator of generalized harmonic number H((p-1)/2,2p)= Sum[ 1/k^(2p), {k,1,(p-1)/2}] divided by p^2 for prime p>3. 0

%I #5 Feb 12 2019 08:42:33

%S 41,1599366601,10877829357646990581304675244472669289,

%T 100935935338172297894217692920950359818733561,

%U 9217176064595104612826996436899733706027947436610177335077693637792069056822883934927465549747441

%N Numerator of generalized harmonic number H((p-1)/2,2p)= Sum[ 1/k^(2p), {k,1,(p-1)/2}] divided by p^2 for prime p>3.

%C Generalized harmonic number is H(n,m)= Sum[ 1/k^m, {k,1,n} ]. The numerator of generalized harmonic number H(p-1,2p) is divisible by p^2 for prime p>3 (see A120290(n)). The numerator of generalized harmonic number H((p-1)/2,2p) is divisible by p^2 for prime p>3.

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/HarmonicNumber.html">Harmonic Number</a>

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/WolstenholmesTheorem.html">Wolstenholme's Theorem</a>

%F a(n) = Numerator[ Sum[ 1/k^(2*Prime[n]), {k,1,(Prime[n]-1)/2} ]] / Prime[n]^2 for n>2.

%e Prime[3] = 5.

%e a(3) = Numerator[ 1 + 1/2^10 ] / 5^2 = 1025 / 25 = 41.

%t Do[p=Prime[k];f=0;Do[f=f+1/n^(2p);g=Numerator[f];If[IntegerQ[g/(p)^2],Print[{p,g/p^2}]],{n,1,(p-1)/2}],{k,1,100}]

%Y Cf. A120290, A119722, A001008, A007406, A007408, A007410.

%K frac,nonn

%O 3,1

%A _Alexander Adamchuk_, Jan 13 2007

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Last modified August 10 23:32 EDT 2024. Contains 375059 sequences. (Running on oeis4.)